How many bytes would s9 9 v99 occupy

WebJan 17, 2013 · If this "number" is always guaranteed to have the same format: 7 digits, a decimal point and 2 more digits after the decimal, the classic way of doing this in COBOL is: 01. 02 NUM-AS-PIC PIC X (10). 03 NUM-EDITED REDEFINES NUM-AS-PIC PIC 9 (7).99. 01 NUM-DEEDITED PIC 9 (7)V99. MOVE '1234567.89' TO NUM-AS-PIC <- alpha-numeric move … WebData name length Length in COBOL 9(01) to 9(04) 2 bytes 9(05) to 9(09) 4 bytes S9(10) to S9(18) 8 bytes COMP-1:In this case the data item will be represented in one word in the floating point form the number is actually represented in hexadecimal format and is suitable for arithmetic operations. The PICTURE Clause cannot be specified for COMP-1 ...

can we declare s9(9)v9(9) in cobol ? if yes how many bytes

WebApr 14, 2024 · 9 (5)-9 (9) = 4 bytes 9 (10)-9 (18) = 8 bytes.. 9 (3)v9 (7) occupies 8 bytes but the question itself wrong COMP variable doesnt have a PIC clause bcz it already contains … WebApr 22, 2006 · The COMP occupies Int (n/2) 4 bytes and COMP-3 occupies Int ( (n/2)+1) bytes. So using this we get the results as : S9 (4) COMP - Int (4/2) = 2 bytes S9 (5) COMP - … great roasts 2021 https://mavericksoftware.net

how many bytes does s9(15) occupy in comp1 comp2 and comp3

WebJan 8, 2003 · On the other hand, a COBOL S9 (9)V99 COMP-3 is a packed decimal field and this is 2 bytes. Let me explain why. A packed decimal field is represented as HEX digits … http://www.3480-3590-data-conversion.com/article-packed-fields.html WebJan 2, 2024 · 03 num-2 pic s9(5)v99 comp. 03 num-3 pic s9(5)v99 comp-3. Share. Improve this answer. Follow answered Jan 3, 2024 at 0:57. Bruce Martin Bruce Martin. 10.3k 1 1 gold badge 26 26 silver badges 37 37 bronze badges. Add a comment Your Answer Thanks for contributing an answer to Stack Overflow! ... flora and fauna in palawan

Calculating space for COMP variables -IBM Mainframes

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How many bytes would s9 9 v99 occupy

How to REDEFINE and perform arithmetic on a PIC X clause in COBOL

WebDec 9, 2024 · 01 WS-NUM PIC S9(5)V9(3) USAGE IS DISPLAY. It requires 8 bytes as sign and decimal doesn't require any byte. 01 WS-NUM PIC 9(5) USAGE IS DISPLAY. It requires 5 bytes as sign. COMPUTATIONAL / COMP Data item is stored in binary format. Here, data items must be integer. http://computer-programming-forum.com/48-cobol/8642e0b624be51c3.htm

How many bytes would s9 9 v99 occupy

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WebHow many bytes would S9 (9)V99 occupy? A) 11 B) 12 C) 6 D) 13 Can index be manipulated using ADD & SET verbs A) Yes B) No (Only Set) Identify the correct statement. A) … WebAnswer / ananta. In pic 9.99 there is dicemal which ocupy space like when we. calculat number of bytes inthis there is 4bytes where as. pic 9v99. has assumed decimal it contains only 3bytes.

WebAug 7, 2024 · S9 (9)V99 comp-3 can hold values in the range of +999,999,999.99 to -999,999,999.99. Each 2 digits takes up 1 byte of a packed decimal, with the sign taking up the high-order nybble. Upvote • 0 Downvote Add comment Report Still looking for help? Get the right answer, fast. Ask a question for free Get a free answer to a quick problem.

WebOn the other hand, a COBOL S9(9)V99 COMP-3 is a packed decimal field and this is 2 bytes. Let me explain why. A packed decimal field is represented as HEX digits followed by a C or D as the last HEX digit for the sign. In this case, S9 means it is a signed numeric field. The (9)V99 means that this number is composed of 1 integral position Webhow many bytes does s9 (15) occupy in comp1 comp2 and comp3 ?.. Answer / rana. COMP1 and COMP2 are the Single precision (Full word - 4. bytes) and Double precision (Double word - 8 bytes) respectively. They don't contain the Picture Clause. COMP-3 will contain 8 Bytes.

WebOct 3, 2016 · S9 (9)V99 is X'99999999999S' or six bytes. S9 (8)V99 is X'09999999999S' or six bytes. S9 (7)V99 is X'999999999S' or five bytes. For COMP, I suggest that you look it …

WebJan 8, 2003 · (9)V99 means that this number is composed of 1 integral position followed by 2 decimal places. The V in the V99 is implies that there are decimal places to follow. For example: If the number... great roast beefWebs9 (9)v9 (9) Here v stands for assumed decimal point so it will occupy. only 18 bytes (9+9)...if instead of s9 (9)v9 (9) it is coded as. s9 (9).9 (9) then it is going to occupy 19 … flora and fauna - grassland biome weebly.comWebJun 24, 2004 · If OUT-AMT is not used in this program (and it's unlikely that it is), it is not necessarily an error as the cited comp-3 field does, in fact, occupy 9 bytes. I would have either defined it as filler, or, more accurately, defined it to match AMOUNT of IN-REC (including the COMP-3). great roasted brussel sprout recipesWebJun 24, 2004 · 05 OUT-AMT PIC S9(15)V99. or if you want numeric edited: 05 OUT-AMT PIC -(15)9.99 BLANK WHEN ZERO. Hope This Helps, PH. ... occupy 9 bytes. I would have … flora and fauna langley bcWebAug 26, 2024 · For WS-VALC PIC S9 (3) USAGE IS COMP-3, so here we can take it as (3+1)/2 which is equal to 2bytes size. Similarly, in the 3byte variable which is WS-VALD PIC S9 (4) USAGE IS COMP-3, so here we can take it as (4+1)/2 which is equal to 2.5 (rounded off) so it will take 3bytes. 10. How to Install COBOL on MacOS? Previous Program Structure of … flora and fauna learning centerWebPIC S9(5) ZD5. ZD for zoned-decimal PIC S9(5)V99 ZD7.2 Field is 7 bytes long, PIC S9(5)V999 ZD8.3 Field is now 8 bytes, and last 3 digits are decimals PIC S9(5)V99 COMP-3 PD4.2 4 bytes long, of which last 2 digits are decimals PIC 9(5)V99 COMP-3 PK4.2 Same as above but unsigned (this is rare) PIC 9(8) COMP IB4. Integer binary (signed) YYMMDD8. flora and fauna international belizeWebAug 3, 2001 · The variable PARTIAL-MESSAGE should have 14 (FILLER) + 14 (VALUE2) = 28 bytes. Adding to that, the first FILLER (4 bytes) + VALUE1 (2 bytes -- even though, if the value is 1, the supressed zero is replaced by a space) = 6 bytes. And then the entire value of PARTIAL-MESSAGE (28 bytes) for a grand total of 34 bytes for ENTIRE-MESSAGE. flora and fauna in philippines